SPSS Homework 4 Instructions
Two-Way
ANOVA
Part One:
Note: For the two-way
ANOVA, you will be expected to create a line graph as covered
in the SPSS
tutorial in the Course Content (and not a boxplot as in the
textbook). This
applies to future cumulative questions as well.
Green & Salkind:
Lesson 26, Exercises 1, 4, 5, 6, 7, and 8
The following helpful tips are numbered to correspond with
the exercise number to which they refer (a dash indicates
that no tips are
needed):
1.
Instead of identifying these values on your output, as
the text states, please write them into your Word file as
written answers for #1 a, b, c, and d. (2 pts for output; a-d = 2
pts each)
a. 3×3 Anova was conducted to investigate the effects of
reinformecment
schedules and arithmetic problem solving performance of
second grade students
the F value of the main effect was shown as 25.034 the total
GPA mean was b.
.196 with the c. effect size of ________ and d. the p value
for the reinforce type main effect is .000
Tests of Between-Subjects Effects
Dependent
Variable: Scores on an arithmetic
problem-solving test
Source
Type III Sum of Squares
df
Mean Square
F
Sig.
Partial Eta Squared
Corrected Model
1927.455a
5
385.491
19.662
.000
.621
Intercept
56204.182
1
56204.182
2866.674
.000
.979
schedule
490.909
1
490.909
25.039
.000
.294
reinfor
1249.182
2
624.591
31.857
.000
.515
schedule * reinfor
187.364
2
93.682
4.778
.012
.137
Error
1176.364
60
19.606
Total
59308.000
66
Corrected Total
3103.818
65
a. R Squared = .621 (Adjusted R
Squared = .589)
4.
Produce a line
graph instead of a boxplot for this problem. Follow
directions in course
SPSS tutorial for setting up a line graph. (2 pts)
5.
Conduct a two way ANOVA to evaluat difference among the
groups, according to gender and disability status of the
child, in the amount
of time fathers spent playing with their children (2 pts)
Between-Subjects Factors
Value Label
N
Disability status of the child
1
Typically Developing
20
2
Physical Disability
20
3
Mental Retardation
20
Gender of Child
1
Male
29
2
Female
31
Descriptive Statistics
Dependent
Variable: play
Disability status of the child
Gender of Child
Mean
Std. Deviation
N
Typically Developing
Male
7.30
1.829
10
Female
6.80
2.201
10
Total
7.05
1.986
20
Physical Disability
Male
3.00
1.563
10
Female
3.40
1.897
10
Total
3.20
1.704
20
Mental Retardation
Male
3.22
1.716
9
Female
4.00
1.612
11
Total
3.65
1.663
20
Total
Male
4.55
2.613
29
Female
4.71
2.369
31
Total
4.63
2.470
60
Levene’s Test of Equality of Error Variancesa
Dependent
Variable: play
F
df1
df2
Sig.
.427
5
54
.828
Tests the null hypothesis that the
error variance of the dependent variable is equal across
groups.
a. Design: Intercept + disable +
gender + disable * gender
Tests of Between-Subjects Effects
Dependent
Variable: play
Source
Type III Sum of Squares
df
Mean Square
F
Sig.
Partial Eta Squared
Corrected Model
182.278a
5
36.456
11.081
.000
.506
Intercept
1276.571
1
1276.571
388.025
.000
.878
disable
178.579
2
89.289
27.140
.000
.501
gender
.763
1
.763
.232
.632
.004
disable * gender
4.294
2
2.147
.653
.525
.024
Error
177.656
54
3.290
Total
1648.000
60
Corrected Total
359.933
59
a. R Squared = .506 (Adjusted R
Squared = .461)
Estimates
Dependent
Variable: play
Disability status of the child
Mean
Std. Error
95% Confidence Interval
Lower Bound
Upper Bound
Typically Developing
7.050
.406
6.237
7.863
Physical Disability
3.200
.406
2.387
4.013
Mental Retardation
3.611
.408
2.794
4.428
Pairwise Comparisons
Dependent
Variable: play
(I) Disability status of the child
(J) Disability status of the child
Mean Difference (I-J)
Std. Error
Sig.b
95% Confidence Interval for Differenceb
Lower Bound
Upper Bound
Typically Developing
Physical Disability
3.850*
.574
.000
2.700
5.000
Mental Retardation
3.439*
.575
.000
2.286
4.592
Physical Disability
Typically Developing
-3.850*
.574
.000
-5.000
-2.700
Mental Retardation
-.411
.575
.478
-1.564
.742
Mental Retardation
Typically Developing
-3.439*
.575
.000
-4.592
-2.286
Physical Disability
.411
.575
.478
-.742
1.564
Based on estimated marginal means
*. The mean difference is significant
at the .05 level.
b. Adjustment for multiple
comparisons: Least Significant Difference (equivalent to no
adjustments).
6.
I would use a three way comparison I would say by
looking at the graph and data the data shows some
significance and in order to
maintain the intergrity of the study and data a three way
comparison would be
used.(2 pts)
7.
All homework “Results sections” should follow the
example given in the Course Content document “Writing Results
of Statistical
Tests in APA Format” (note: you do not have to refer to a
figure). (2 pts)
Tests of Between-Subjects Effects
Dependent
Variable: play
Source
Type III Sum of Squares
df
Mean Square
F
Sig.
Partial Eta Squared
Corrected Model
182.278a
5
36.456
11.081
.000
.506
Intercept
1276.571
1
1276.571
388.025
.000
.878
disable
178.579
2
89.289
27.140
.000
.501
gender
.763
1
.763
.232
.632
.004
disable * gender
4.294
2
2.147
.653
.525
.024
Error
177.656
54
3.290
Total
1648.000
60
Corrected Total
359.933
59
a. R Squared = .506 (Adjusted R
Squared = .461)
A 3×3 Anova was conducted to determine the
effects of three disability conditions (mental retardation,
typical
development, and physical disability) and two genders. F
(1,54) = 27.140, p
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