Question (1)By arranging the data in ascending order, we have4, 10, 11, 13, 14, 15, 25, 29, 33, 33, 35, 43, 51, 58 and 64Question (2)The median is gotten by eliminating data set from opposite ends to reveal either 2 or one last standing data.Median is 29Question (3)The lower quartile = 1/4 (N +1)Where N is the size of the data set.For this case N = 15Q1 = 1/4 (15 +1)Q1 = 1/4 16Q1 = 16/4 = 4It implies that the lower quartile is in the 4th position which is 13.Question (4)The upper quartile = 3/4 (N + 1)Q3 = 3/4 (15 +1)Q3 = 3/4 16Q3 = 12It implies that the upper quartile is in the 12th position which is 51.Question (5)Question (6)Interquartile range = Q3 - Q1/2= 12 - 4/ 2 = 8/2 = 4.It implies that the inter quartile range is at the 4th position and that is 13.Question (7)Range = 64 - 4 = 60.Question (8)The range is simply the difference between largest and smallest value in the data set.A range is a number and not a position.The Interquartile range is the difference between the upper quartile and the lower quartile divided by 2.The answer gotten is not a number but a position whichmust be traced back to the data to get a number.Question 9Question (10)We have a total of 11 studentsQuestion (11)The interview method.This method is simply asking the students for their respective heights and taking notes of itQuestion (12)Other data that we can collect from the students includesWeight (in kg)Age (in ...
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